1. Find the value of x for the equality
Solution:
The solution is not possible.
As, in L.H.S, x > 3
And in R.H.S, x < 3
So, no values of x are possible.
2. The base or radix of the number system such that the following equation holds:
Solution:
First, convert it to decimal.
r = 0 is not possible, (base 0). But r = 5 is possible. So, r = 5
3. Find radix or base of the number system such that
is valid. Find r for which it is valid.
Solution:
So, definitely r ≥ 7 because has 0 to r – 1.
So, for r ≥ 7 or r > 6, it is valid.
We can solve it another way by converting it to a decimal system.
And highest digit is 6, so, the value of the base can be any number r ≥ 7or r > 6.
Consider the above equation where x and y are unknown. Find the number of possible solutions i.e. how many possible solutions for x and y.
Important Note:
Radix or base never 0 or fractional or negative number, it is always an integer number.
Solution:
From it is clear that x should be greater than 4 because then it has x different number 0 – x – 1.
So, x > 4 or x ≥ 5.
And from this, it is clear that y should be less than 8 because contain 0 – 7 values.
So, y < 8
Now we convert it to decimal to know the exact number of solution for x and y for which
So,
Answer: 5 possible values of x and y