CREATE OWN LIBRARY

Given a string S contains of upper/lower case alphabets and empty space characters ‘ ‘, return the length of last word (last word means the last appearing word if we loop from left to right) in the string

If the last word does not exist, return 0

Note: A word is defined as a maximal substring consisting of non space characters only

Example:

I/P: “Hello world”

O/P: 5

Step 1: Remove the white spaces from both sides

Step 2: Split the string into list based on spaces

Step 3: Return 0 if length of the list is 0 else find the last index using – 1 and return its length.