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Inverted Pyramid Number Pattern
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Inverted Pyramid Number Pattern:
Here in this pattern printing, the number of lines of the pattern is taken as the input. Three for loops are used to display the pattern. The first for loop (the outer for loop) is used to count the line number so the loop is from n to 1 (here the number of lines are counted in reversed order). The second for loop is used to print the spaces before the elements at each line. for ith line the numbers are printed from 1 to i.
Algorithm
INPUT: the number of lines
OUTPUT: the aforesaid pattern
PROCESS:
Step 1: read n [the number of lines]
Step 2: for i=n to 1 repeat
For k=1 to n-i repeat
Print “ “
[End of ‘for’ loop]
For j=1 to i repeat
Print j
[End of ‘for’ loop]
Move to the next line
[End of ‘for’ loop]
Step 3: stop.
Code
Time Complexity:
for(i=n;i>=1;i--)--------------------------------------- n
{ for(k=1;k<=n-i;k++)------------------------ n-i
printf(" ");
for(j=1;j<=i;j++)----------------------------- i
printf("%d ",j);
printf("\n");
}
The complexity is: O(n*(n-i+i))=O()
