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Series 15

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The program is written here to print the below series

# For loop is used here to print the series.

# The value of the first term of the series is 2.

# The value of the nth term of the series is: (13 × n × (n – 1)) / 2 + 2

For example, if the input is 5,

1st term: (13 × 1 × 0)/2 + 2 = 2

2nd term: (13 × 2 × 1)/2 + 2 = 15

3rd term: (13 × 3 × 2)/2 + 2 = 41

4th term: (13 × 4 × 3)/2 + 2 = 80

5th term: (13 × 5 × 4)/2 + 2 = 132

Therefore, the series will be: 2, 15, 41, 80, 132

INPUT: Number of terms

OUTPUT: The aforesaid series upto nth term

PROCESS:

Step 1: [Taking the input]

Read n [Number of terms]

Step 2: [Printing the series]

Set t<-0

Print "The series is: "

For i=1 to n repeat

Set t<-(13 × i × (i - 1)) / 2 + 2

Print t

[End of ‘for’ loop]

Step 3: Stop.

TIME COMPLEXITY:

for(i=1;i<=n;i++)----------------------------------- O(n)

{

t=(13 * i * (i - 1)) / 2 + 2;

printf("%d ",t);

}

The time complexity of this program is O(n) where ‘n’ is the number of terms of the series.

SPACE COMPLEXITY:

The space complexity of this program is O(1) as it requires a constant number of memory spaces for any given input.