Prime Numbers from 1 to 100

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Before see the program follow the prime number checking program.

A number is called a prime number if the number is only divisible by 1 and itself. The prime numbers have exactly two factors- 1 and the number itself. 


For example,  if the number is 5. 5 is only divisible by 1 and 5. The number of factors of 5 is 2. So, 5 is a prime number.

If the number is 4, it is divisible by 1, 2, and 4. So, instead of 1 and 4, it has another factor 2. The number of factors of 4 is 3. So, it is not a prime number.


So, the main logic of the program is to take the number as input and the number of factors are counted. If the number of factor is 2 then it is a prime number otherwise it is not a prime number.

The program is written here to find the prime numbers between 1 and 100. For each number it is checked for prime, if it is prime then it will be printed.


OUTPUT: Prime numbers between 1 and 100.
Step 1: [printing the prime numbers between 1 and 100]
	For j=1 to 100 repeat
		Set c<-0
		[counting the number of factors]
		For i=1 to j repeat
			If j mod i=0 then
				Set c<-c+1
			[End of ‘if’]
		[End of ‘for’ loop]
		If c=2 then
			Print j
		[End of ‘if’]
Step 2: Stop.


Time Complexity:


                {    c=0;

                      //counting the number of factors







                                                printf("%d ",j);



The time complexity of finding prime numbers here is O(n*j) where n is the number of elements to be checked for prime and ‘j’ is each number to be checked. Here, the value of n is 100. For the simplicity of the program here the loop to check prime is executed from 1 to j.

But for more optimization, we can check from 2 to j because a number ‘j’ can have maximum j  number of factors. So, we can say the most optimized complexity is O(j).

Space Complexity:

The space complexity of this program is O(1) as it requires a constant number of memory spaces to find the prime numbers between 1 and 100.